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Application.GetOpenFilename from a specified directory
Hello!
I have Excel 2003 and I already have a macro to popup a open file dialog. However, it always starts at "C:\My Documents" folder. I want it to browse files to open from a specific directory. How is this done? Note that I already have the "ChDir" on the line above the "Application.GetOpenFilename" but the browsing does not start from the specified directory. Thanks in advance for your response. |
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Re: Application.GetOpenFilename from a specified directory
This is small example
Change MyPath = ThisWorkbook.Path to your folder MyPath = "C:\Users\Ron\test\" Sub test() Dim FName As Variant Dim wb As Workbook Dim MyPath As String Dim SaveDriveDir As String SaveDriveDir = CurDir MyPath = ThisWorkbook.Path ChDrive MyPath ChDir MyPath FName = Application.GetOpenFilename(filefilter:="Excel Files (*.xls), *.xls") If FName <> False Then Workbooks.Open (FName) End If ChDrive SaveDriveDir ChDir SaveDriveDir End Sub -- Regards Ron de Bruin http://www.rondebruin.nl/tips.htm "C C" <someone@atsbcglobal.net> wrote in message news:%23zMfy0nuIHA.2068@TK2MSFTNGP05.phx.gbl... > Hello! > > I have Excel 2003 and I already have a macro to popup a open file dialog. > However, it always starts at "C:\My Documents" folder. I want it to browse > files to open from a specific directory. How is this done? Note that I > already have the "ChDir" on the line above the "Application.GetOpenFilename" > but the browsing does not start from the specified directory. > > Thanks in advance for your response. > > |
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